Un tren de carga va a una velocidad constante de 60 km/h y pasa por un túnel de 340 m de largo. ¿Cuánto mide el tren, si es que para cruzar completamente el túnel se demora tres cuartos de minuto?

the length would be 410.15m

Step-by-step explanation:

The computation of the length is as follows;

Length = 340m

Let us assume x be train length

Now

the distance traveled by the train is  (L + x)

d = L + x

v = 60 km ÷ h

= 16.67 m / s

And,

t = (3 ÷ 4) (60)

= 45s

Now

d = vt

L + x = (16,67) (45)

x = (16,67) (45) - 340m

x = 410.15m

Hence, the length would be 410.15m

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12

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