An Air Force plane left London at the same time as a jet. The planes flew in opposite directions. The jet flew at a speed of 375 km/h. After four hours they were 2260 km apart. How fast did the Air Force plane fly?

190km/h

Step-by-step explanation:

Since the jet flies 375 km per hour then in four hours it is going to fly 1500

375*4=1500

As they are 2260km apart you would subtract 1500 from 2260

2260-1500=760

You would then divide 760 by four to find out how many km per hour

760÷4=190

There fore your answer is 190 km/h

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

50x5=$250

step-by-step explanation: