A car of mass 2400kg moving with a velocity 20m/s is stopped by applying brakes in 10s. Calculatethe ret-arding force(I had to put da dash cuz found it INAPPROPRIATE read it without the dash).

Acceleration force = 2 m/s²

Force = - 4,800 N

Given:

Mass (m) = 2,400 kg

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 m/s  

Time taken (t) = 10 s        

Find:

Acceleration force

Force

Computation:

v = u + at  

0 = 20 + (a)(10)  

Acceleration force = 2 m/s²

f = ma  

f = 2,400 X (-2)

Force = - 4,800 N

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

y-y1=m(x-x1)

y-1=1(x-8)