Write the equation of the line that passes through the points (7,3) and (2,-6). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

y  = (9/5)x - 9.6 in slope intercept (not sure if this counts as reduced?) and y + 6 = 9/5 ( x - 2 ) point slope

Step-by-step explanation:

We need to find the point slope formula. This is y-y1 = m(x-x1). First, we need to find the slope, and we can start to begin to make our equation from there. Slope = rise/run, so 9/5 should be our slope.

y - y1 = 9/5(x - x1) is our new eqn.

Then, we can put one of the points from our line into our eqn, since both pass through our eqn, we can use either point for our calculations.

Sticking with just the first point and substitutuing in values, we get:

y + 6 = 9/5 ( x - 2 ) and now we have to simplify.

y = 9x/5 - 18/5 - 6

y = 9x/5 - (15/5 + 3/5) - 6

y = 9x/5 -3.6-6

y = 9x/5 -9.6

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

114 plus 113 times 2 and 114 times 3