Please help! (Will give BRAINLIEST) While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty
percent of her students answered question number 14 with multiple choice option B, while the other sixty percent
answered A or C.
Question #14 from Mrs. Jones's students' most recent quiz:
14) Solve the single variable equation for n.
3(-n +4) + 5n = 2n
an=3
b. no solution
c. Infinitely many solutions
Part 1: Use Inverse operations and rules of equation solving to determine the correct answer to Mrs. Jones's quiz
question number 14. Include all of your work in your final answer.
Part 2: Use complete sentences to compare the simllarities and differences of each of the multiple choice answer
options A-C. In your answer, rationalize why a student would choose each of the options as the correct answer.

What is the arc length when θ =pi over 3 and the radius is 5 cm? (5 points) 5 pi over 3 cm 10 pi over 3 cm 16 pi over 3 cm pi over 3 cm

What are the first 4 terms in the multiplication pattern given by the formula 2×4n

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.