Mario recorded the height of his teammates. Height (in inches) 64 53 60 60 56 58 51 55 60 Part C: What is the interquartile range of the data? A. 4.5 B. 6 C. 5 D. 5.5

B.) 6

Step-by-step explanation:

Given the data:

64 53 60 60 56 58 51 55 60

Reordered data : 51, 53, 55, 56, 58, 60, 60, 60, 64

Interquartile range = upper quartile (Q3) - Lower quartile (Q1)

Q3 = 3/4(n+1)th term

n = sample size = 9

Q3 = 3/4(9+1) = 3/4 (10) = 30/4 = 7.5 th term

Q3 = 60

Q1 = 1/4 (n + 1) th term

Q1 = 1/4(9+1) = 1/4 (10) = 10/4 = 2.5 th term

Q1 = (53 + 55) / 2

Q1 = 54

Q3 - Q1

60 - 54 = 6

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the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet