The spinner shown is divided into congruent sections that are labeled from 1 through 7. If the spinner is spun one time, what is the probability of the arrow not landing on a section labeled with an odd number?

3/7

Step-by-step explanation:

The number of possible results are;

1, 2 , 3 , 4 , 5, 6 , 7 = 7

odd numbers here are;

1, 3 , 5 and 7

non-odd numbers are 2, 4 and 6

So the section not labeled with an odd number is 3

Hence the probability here is that;

3/7

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