Cara graphs a system of linear equations and identifies a point as the solution. Where is the point located?
A. the origin
B. the intersection of the two lines
C. the x-intercept
D. the y-intercept

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

do you have the measurements?

could

step-by-step explanation:

u send me a picture of ur work

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval