If a six-sided cube is rolled, what is the probability that it will land on a 4 or a 6?

Step-by-step explanation:

What is probability of rolling a 1, 2, 3, 4, or 5 on a 6-sided cube?

If your 6-sided cube is the usual casino die used in the game of , then

P(rolling a 6)

=16⟹  

P (rolling something other than a 6) = P(rolling a 1, 2, 3, 4, or 5) =

1 - P(rolling a 6) =

1−16=66−16=56.  

Don’t let the word or throw you off in answering this problem.

i think is g(1)=-1.

hope that i can