Solve the equation. 5t^3 +40t^2 = -80t a. t= 0 and t= 4
b. t= -4 and t=0
c. t= -4 and t= 5
d. t= 4

Option 'A' is true.

Step-by-step explanation:

Given the equation

Add 80 to both sides

Simplify

as 5t³ + 40t² + 80t = 5t (t + 4)²

5t (t + 4)² = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

       or        

solving

subtract 4 from both sides

Simplify

Therefore, the solution to the equation is:

Hence, option 'A' is true.

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is: