FEE Which equations represent the line that is parallel to 3x - 4y = 7 and passes through the point (-4,-2)? Select two
options
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VX
Oy=-3x + 1
0 3x - 4y = -4
0 4x - 3y = -3
Oy-2 =(-4)
Oy +2 = (x + 4)

The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

Step-by-step explanation:

The slope-intercept form of the line equation

where

Given the line

3x - 4y = 7

writing in the slope-intercept form

4y = 3x - 7

dividing both sides by 4

4y/4 = 3/4x - 7/4

y = 3/4x - 7/4

Now, comparing with the slope-intercept form of the line equation

y = 3/4x - 7/4

The slope of the line m = 3/4

We know that parallel lines have the same slopes.

Therefore, the slope of the parallel line is: 3/4

now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

where m is the slope of the line and (x₁, y₁) is the point

substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

Thus, the equation in the point-slope form of the line equation is:

Simplifying the equation

Subtract 3 from both sides

Multiplying the equation by 4

Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.