Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost 25$ and same-day tickets cost 20$ . For one performance, there were 50 tickets sold in all, and the total amount paid for them was 1150$ . How many tickets of each type were sold?

Number of advance tickets sold = 30

Number of same-day tickets sold = 20

Step-by-step explanation:

Let,

x be the number of advance tickets sold

y be the number of same-day tickets sold

According to given statement;

x + y = 50      Eqn 1

25x + 20y = 1150     Eqn 2

Multiplying Eqn 1 by 25

25(x+y=50)

25x + 25y = 1250     Eqn 3

Subtracting Eqn 2 from Eqn 3

(25x+25y)-(25x+20y) = 1250 - 1150

25x + 25y - 25x - 20y = 100

5y = 100

Dividing both sides by 5

Putting y = 20 in Eqn 1

x + 20 = 50

x = 50 - 20

x = 30

Hence,

Number of advance tickets sold = 30

Number of same-day tickets sold = 20

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

step-by-step explanation: