Find the minimum value of the function f(x)=x^2+5x-6

The vertex of Parabola is the maximum/minimum point depending on the value of a.

h-value

k-value

The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.

This is Calculus method. We simply differentiate the function then substitute y' = 0.

Substitute f'(x) = 0

Substitute x = -5/2 in the original equation.

the first one, all those points on the line just make a strait line.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.