A bag contains eleven equally sized marbles, which are numbered. 11 numbered marbles are shown. Marbles 2, 6, 7, 8, 10 and 11 are white. Marbles 1, 3, 4, 5, and 9 are shaded purple.

What is the probability that a marble chosen at random is shaded or is labeled with a multiple of 3?

Two-elevenths

The probility would be 3/11

Step-by-step explanation:

The reason being is because the multipies

of 3's are 3,6,9, and so forth

Hope this helps!

6/11-D

Step-by-step explanation:

just did it

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

they are simplified

step-by-step explanation: