A certain radioactive material is known to decay at a rate proportional to the amount present. If initially there is 50 mg/L of the material present and after 2 hours it is observed that the material has lost 10 percent of its original concentration, find (a) an expression for the concentration of the material remaining at any time.

Step-by-step explanation:

A certain radioactive material is known to decay at a rate proportional to the amount present.

This means that the situation can be described by the following differential equation:

In which r is the decay rate.

Solving the differential equation by separation of variables, we have that:

Integrating both sides:

In which K is the integrative constant.

Applying the exponential to both sides, to remove the ln, we get:

In which K is the initial amount present.

Initially there is 50 mg/L

This means that .

After 2 hours it is observed that the material has lost 10 percent of its original concentration

This means that . So

So

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6