What is the equation of the line that is perpendicular to 3x -6y =2 and contains the point (-2,--5)

y=-2x-12

Step-by-step explanation:

first, putt 3x-6y=2 in standard form:

subtract 3x from both sides: -6y=-3x+2

divide both sides by -6 to isolate y: y=1/2x-1/3

if the other line is perpendicular to this, you must find the slope by finding the opposite reciprocal of 1/2x: -2

now we have 2 points a slope, so we use the point-slope formula: y-y1=m(x-x1)

y+2=-2(x+5)

Use the distributive property: y+2=-2x-10

subtract 2 for both sides to isolate y: y=-2x-12

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