0-5(4 β 3v) = -3(+5)
Mathematics, 28.01.2021 21:30 iwantcandy2002
Which equation has infinitely many solutions?
O-5(-4+30) =3 (5v - 4)
0-5(4 β 3v) = -3(+5)
O 4-5 β 3v) = -4(3u +5)
O 4(5 + 3) = 4(50 - 3)
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Answers: 1
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Which equation has infinitely many solutions?
O-5(-4+30) =3 (5v - 4)
0-5(4 β 3v) = -3(+5)
0-5(4 β 3v) = -3(+5)
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