Evaluate b-\left(-\dfrac{1}{8}\right)+cb−(− 8 1 )+cb, minus, left parenthesis, minus, start fraction, 1, divided by, 8, end fraction, right parenthesis, plus, c where b = 2b=2b, equals, 2 and c = -\dfrac{7}{4}c=− 4 7 c, equals, minus, start fraction, 7, divided by, 4, end fraction.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.