Consider the exponential function f(x) = 2(3^x) and its graph.
ty
8
y = f(2)
The initial value of the function is
The base of the function is v
The function shows exponential
4
-8
-4
4.
8
-4
-8

I don't know

Step-by-step explanation:

I'm so sorry honestly but have a great day :)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: