there are 5 red counters and 3 blue counters in bag A. there are 4 red counters in bag B. Tina takes at random a counter from each bag. what is the probability that Tina takes two blue counters

The probability is 0

Step-by-step explanation:

From the first bag, the total number of counters is 5 + 3 = 8

The probability of taking a blue counter from the first bag is the number of blue counters divided by the total number of counters

Mathematically, we have this as;

3/8

For the second bag, all the counters are red with no blue counter

So the probability of taking a blue counter here is 0

Now, the probability that he takes a blue counter in A and a blue counter in B will

be;

3/8 * 0 = 0