Help me solve this problem its urgent. In the above given figure( attached photo) , M is the point on side QR. Fill in the blanks using symbol =, > or < to complete the statement.

1) PM _ PQ + QM
2) PM _ PR + MR
3) PM _ 1/2 (PQ+PR+QR)

1) PM < PQ + QM

2) PM < PR + MR

3) PM < 1/2 (PQ + PR + QR)

Step-by-step explanation:

This problem is based on the Pythagorean Theorum Equation

which states that a right triangle with sides a, b and hypotenuse can be written mathematically as hypotenuse =

We can rewrite each line segment of the diagram into variables to simplify this problem and use the Pythagorean equation:

Line PQ = Hypotenuse 1, Line PR = Hypotenuse 2, Line PM = Side B, Line QM = Side A, Line MR = Side C

With all the line segments simplified into variables you can separate the diagram into 2 seperate triangles. Triangle 1 has H1, A, B and Triangle 2 has H2, C, B

Using the Pythagorean equation for both triangles you get:

H1 =   and H2 =  

Now you can assign random values for each variable and compare the problem statements.

For Triangle 1 lets assign variables A = 1, B = 2, and H1 = = = 1.73  For Triangle 2 lets assign variables C = 3, B = 2 and H2 = = 3.6  

For the final step you can directly compare the statements and see which symbol is correct.

1) B ____ H1 + A is equivalent to  2  ____ (1.73 + 1),  which is turns out to be  2 < 2.73   The answer is  <

2) B ____ H2 + C is equivalent to 2 ____ (3.6 + 3), which turns out to be

2 < 6.6    The answer is < again

3) B ____ 1/2 (H1 + H2 + (A+C)  is equivalent to  2 _____ [1/2] (1.73 + 3.6 + 1 + 3), which turns out to be  2 < 4.67     The answer is <  again

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.