K+a=500
3k+10a=3,600
find k and a using elimination plss helppp

a=300 and k=200

Step-by-step explanation:

Multiply the first equation by -10,and multiply the second equation by 1.

−10(a+k=500)

1(10a+3k=3600)

Becomes:

−10a−10k=−5000

10a+3k=3600

Add these equations to eliminate a:

−7k=−1400

Then solve−7k=−1400for k:

−7k=−1400 (Divide both sides by -7)

Now that we've found k let's plug it back in to solve for a.

Write down an original equation:

a+k=500

Substitute200forkina+k=500:

a+200=500

a+200+−200=500+−200(Add -200 to both sides)

a=300

Hope this helps :)

ok then what happened.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!