A car suspension is described with a mass and spring system, as shown in Figure 1 Given an oscillation described by the function: = 0.5(sin(0.7)
Show that:
i) The velocity of the tyre is described by () = 0.35cos (0.7)

ii) The acceleration of the tyre is described by () = −0.245sin(0.7)

PLEASE HELP ME :(

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

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step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

they would have to work 32 hours.