which equation describes a line that contains the point (4,3) and is perpendicular to the line represented by the equation y=2/5x+3?

The equation of the line  that contains the point (4,3) and is perpendicular to the line represented by the equation y=2/5x+3 will be:

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

Given the line

y=2/5x+3

comparing with the  slope-intercept form of the line equation

Thus, the slope of the line is: m = 2/5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:  

slope = m = 2/5

Thus, the slope of the the new perpendicular line = – 1/m = [-1]/[2/5] = -5/2

Using the point-slope form of the line equation

substituting the slope of perpendicular line m = -5/2 and the point (4, 3)

Add 3 to both sides

Therefore, the equation of the line  that contains the point (4,3) and is perpendicular to the line represented by the equation y=2/5x+3 will be:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)