The nth term of a sequence is 7(n + 2).
What are the first four terms?

21, 28, 35, 42

Step-by-step explanation:

You need to do BODMAS / BIDMAS for this

So calculate what's inside the brackets first and then multiply by the 7

So

7(1+2) would be 7(3) which would be 7 x 3 = 21

and so on for the rest

7(2+2) = 28

7(3+2) = 35

7(4+2) = 42

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following