Dan rolls a fair dice 24 times.
How many times would Dan expect to roll an even number?

Assuming a fair, six sided die, 4 would be expected to come up in one sixth of the trials, so 4 times in 24 rolls.

More formally:

Let X be the number of 4s rolled in 24 independent rolls of a fair six sided die. X is then distributed binomially with parameters n and p.

p = Probability of rolling a 4 = 1/6

n = Number of trials = 24

E [X] = np (by the properties of Binomial distribution)

E [X] = 4

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: i wpould go with c

step-by-step explanation: