In ∆ABC, m∠BAC=4x+10,m∠ABC=12x-6,and m∠BCA=3x+5 Use the given information to find the value of x (1 point). Show your work (2 points)
Now that you know x, find the measure of each angle. Show your work (2 points each).
m∠BAC
m∠ABC
m∠BCA
Find the measure of angle 1 and angle 2 (2 points each)
m∠1
m∠2
Angle BAC and Angle FAC are examples of what type of angle pair? (1 point)
Angle BCE and Angle DCA are examples of what type of angle pair? (1 point)

Try this option, note: only calculation is performed, the last two question are missed.

Step-by-step explanation:

to calculate 'x':

the rule: m∠BAC+m∠ABC+m∠BCA=180°; if to substitute m∠BAC=4x+10,m∠ABC=12x-6,and m∠BCA=3x+5, then 4x+10+12x-6+3x+5=180°; ⇔ x=9.

to calculate m∠BAC; m∠ABC; m∠BCA:

m∠BAC=4x+10; ⇒ m∠BAC=36+10=46°;

m∠ABC=12x-6; ⇒ m∠ABC=108-6=102°;

and m∠BCA=3x+5; ⇒ m∠BCA=27+5=32°.

to calculate the angle 1 and 2:

the fule is: m∠1+m∠BAC=180° and m∠2+m∠ABC=180°.

Then m∠1=180-m∠BAC=180-46=134°;

m∠2=180-m∠ABC=180-102=78°.

i dont know

step-by-step explanation:

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!