1. For a party, Susan estimated there would be 14 people in attendance, but only 12 showed up. What was the percent error in her estimation?

2. Find the percent error in this situation:
Estimated value: 231
Actual value: 215

3. Find the percent error in this situation:
Experimental value: 16.5 sec
Theoretical value: 17.1 sec

4. Find the percent error in this situation:
Estimated value: 1081
Actual value: 1150

The formula for percent error is:

((Approximate value -  exact value) / exact value) x 100

1) 14-12 = 2

2/12 = 0.1666

0.166 x 100 = 16.7%  (Rounded to nearest tenth)

2) 231 - 215 = 16

16/215 = 0.74419

0.74419 x 100 = 7.4419% ( Round as needed)

3) 17.1 - 16.5 = 0.6

0.6/16.5 = 0.36364

0.36364 x 100 = 3.6364% (Round off as needed)

4)  1081 - 1150 = -69

-69/1150 = -0.06

-0.06 x 100 = -6% = 6% error

step-by-step explanation:

1. the cylinder is a. 54

2.   a.108 /

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: