Ibrahim and Yessica have $25 in paper money and a lot of quarters and pennies. He has 22 coins and she has 14. Their coins add up to $2.52. They ask you to guess how many quarters and how many pennies they had. WHAT VARIABLES might you need?

The variables are P for pennies and Q for quarters, and solving the equations we can find that they have 9 quarters and 27 pennies.

Step-by-step explanation:

We know that they have quarters and pennies, then the variables that we will use are:

P = total number of pennies

Q = total number of quarters.

Now let's solve the problem.

We know that the value of a penny is $0.01

We know that the value of a quarter is $0.25

We know that he has 22 coins, and she has 14 coins.

Then the total number of coins is 22  + 14 = 36 coins, then:

P + Q = 36

We also know that the total value of these coins is $2.52

then:

P*$0.01 + Q*$0.25 = $2.52

Then we have a system of equations:

P + Q = 36

P*$0.01 + Q*$0.25 = $2.52

To solve it, we need to start by isolate one of the variables in one of the equations, let's isolate P in the first one

P = 36 - Q

Now we can replace this in the other equation:

(36 - Q)*$0.01 + Q*$0.25 = $2.52

Now we can solve this for Q.

36*$0.01 - Q*$0.01 + Q*$0.25 = $2.52

$0.36 + Q*$0.24 = $2.52

Q*$0.24 = $2.52 - $0.36 = $2.16

Q = $2.16/$0.24 = 9

Then they have 9 quarters, and the number of pennies is given by

P = 36 - Q = 36 - 9 = 27

They have 27 pennies.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

(a) the volume of the cone is 20/3 in3

hence, option a is correct.