DeShawn and Totsakan are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of shiny wrapping paper. DeShawn sold 12 rolls of plain wrapping paper and 1 roll of shiny wrapping paper for a total of $59 . Totsakan sold 6 rolls of plain wrapping paper and 8 rolls of shiny wrapping paper for a total of $112. Find the cost each of the rolls of plain wrapping paper and one roll of shiny wrapping paper .

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Step-by-step explanation:

Let p and s represent the costs of plain and shiny rolls of paper, respectively. The given sales let us write two equations in these two unknowns.

  12p +1s = 59 . . . . . DeShawn's sale

  6p +8s = 112 . . . . . Tatsakan's sale

Multiplying the second equation by 2 and subtracting the first, we have ...

  2(6p +8s) -(12p +s) = 2(112) -(59)

  15s = 165 . . . . . . . . . . . . . . . . . . . . . simplify

  s = 11 . . . . . . . divide by 15

Substitute into the second equation to find p.

  6p +8(11) = 112

  6p = 24 . . . . . . . . subtract 88

  p = 4 . . . . . . . . . . .divide by 6

A plain roll costs $4; a shiny roll costs $11.

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step-by-step explanation: