A rectangle has a length of x and a width of 5x cubed+4-x squared. Find the perimeter of the rectangle when the length is 5 feet

1060 feet

Step-by-step explanation:

The computation of the perimeter of the rectangle is as follows;

As we know that

Perimeter of the rectangle = 2 × ( length + width)

where

Length of x = 5

And, the width be 5x^3 - 4x^2

= 5(5)^3 - 4(5)^2  

= 625 - 100  

= 525

Now the perimter is

= 2 × (5 + 525)

= 1060 feet

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5

eight hundred an fifty one point four hundred and fifteen

800+50+1+.4+.01+.005