Subject: Maths Level: High-school

Topic: transforming graphs

Points: 90

PLEASE HELP!

(i have the answer for part i, i just need hel with ii and iii)

Step-by-step explanation:

The function in vertex form is:

i) y = f(x) - 2 = (x - 1)² - 3 - 2 = (x - 1)² - 5 ⇒ h = 1, k = -5

Minimum point:

ii) y = f(2x) = (2x - 1)² - 3 = 4(x - 1/2)² - 3 ⇒ h = 1/2, k = -3

Minimum point:

iii) y = 3f(x) = 3((x - 1)² - 3) = 3(x - 1)² - 9 ⇒ h = 1, k = -9

Minimum point:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)