What is the image of the point (3,2)(3,2) after a rotation of 90^{\circ}90 ∘ counterclockwise about the origin?

= (-2,3)

Step-by-step explanation:

Here, fixed point = origin = (0,0)

Transformation rule for rotation of  counterclockwise about the origin:

Then, the image of the point (3,2) =  (-2,3)

Hence, the image of the point (3,2) after a rotation of  counterclockwise about the origin = (-2,3)

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629