If 8x−5y=−3 is a true equation, what would be the value of 8x−5y+7?

Value of 8x -5y + 7 is 4.

Step-by-step explanation:

Given that:

8x-5y = -3     Eqn 1

It is a true equation.

Now we have to find the value of the given expression

8x -5y + 7

Putting value of 8x-5y from Eqn 1 in the given expression

8x - 5y + 7

-3 + 7

4

Therefore,

8x - 5y + 7 = 4

Hence,

Value of 8x -5y + 7 is 4.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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