Given: x ∥ y w is a transversal of x and y. Prove: ∠4 ≅ ∠5 Parallel lines x and y are cut by transversal w. On line x where it intersects line w, 4 angles are created. Labeled clockwise, from the uppercase left: angle 2, angle 1, angle 3, angle 4. On line y where it intersects line w, 4 angles are created. Labeled clockwise, from uppercase left: angle 6, angle 5, angle 8, angle 7. A 2-column table with 5 rows. Column 1 is labeled statements with the entries x is parallel to y, w is a transversal, angle 4 is congruent to angle 1, angle 1 is congruent to angle 5, angle 4 is congruent to angle 5. Column 2 is labeled reasons with the entries given, given, A, B, C. Complete the two-column proof. A B C

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

b. f(x) = –√x + 3this is the correct answer