Mr. Smith asked his students to record the length of time they read over the weekend. The times are listed in the table. Make a line plot using the data. Then, use the data to respond to the given questions.
0
1/8
2/8
3/8
4/8
6/8
2
4/8
1/4
1/2
3/4
8/8
16/8
1/2
4/4
8/4
Student
1. What was the longest amount of time a student read over the weekend?
Length of
time
(in
hours)
1. find total (common
denominators)
2. find who read more using cart
5. Mr. Smith read 4 hour on
Friday, hour on Saturday,
2 hour on Sunday. Who read
more than Mr. Smith?
SHOW YOUR WORK!
Sam
12
2. What was the shortest amount of time a student read over the weekend?
Lori
112
Violet
3/4
Penelope
14
3. Which amount of time was the most frequent? most often / happened more
George
34
Winnie
V
I
Robbie
%
4. What is the total in hours read over the weekend? SHOW YOUR WORK!
Stefanie
12
Alex
1

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

do you have an easier question cause this shh is hard like theheck

step-by-step explanation: