Brenda is deciding between two landscaping companies for her place of business. Company A charges $25 per hour and a $300 equipment fee. Company B charges $50 per hour and a $150 equipment fee. Let AA represent the amount Company A would charge for tt hours of landscaping, and let BB represent the amount Company B would charge for tt hours of landscaping. Write an equation for each situation. Determine the interval of hours, t, t, for which Company A is cheaper than Company B.

1/6 hours

Step-by-step explanation:

Given data

Company A charges

$25 per hour and a $300 equipment fee

let the number of hours be t

and the total charges be A

A=25+300t1

Company B charges $50 per hour and a $150 equipment fee.

let the number of hours be t

and the total charges be B

y=50+150t2

Equate 1 and 2 we have

25+300t= 50+150t

300t-150t= 50-25

150t= 25

divide both sides by 150

t= 25/150

t=1/6 hours

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )