There are the same remainder 3 when 135, 111, 87, is divided by a certain number. Find the largest possible value of this number yo pl answer quickly the submission is tommorow

12

Step-by-step explanation:

Below numbers are divisible by the number we are looking for:

135 - 3 = 132111 - 3 = 10887 - 3 = 84

Lets find GCF of the three numbers:

132 = 11*2*2*3108 = 2*2*3*3*384 = 7*2*2*3

GCF(132, 108, 84) = 2*2*3 = 12

The largest possible number is 12

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.