In a survey of school students, 64 had taken mathematics course, 94 had taken chemistry course, 58 had taken physics course, 28 had taken mathematics and physics, 26 had taken mathematics and chemistry, 22 had taken chemistry and physics course, and 14 had taken all the three courses. Find how many had taken one course only by using Venn diagram.

106

Step-by-step explanation:

From the information given :

Let:

Mathematics = M

Physics = P

Chemistry = C

n(M) = 64 ; n(C) = 94 ; n(P) = 58

All three (n(MnCnP) = 14

Kindly check attached picture for clearer explanation :

Number of students who took only one subject :

(24 + 22 + 60) = 106

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°