The angle of elevation to an airplane viewed from the control tower at an airport is 15°. The tower is 100 feet high and Pilot Cory reports that the altitude of the airplane is 5100 feet (5000 feet higher than the control tower). How far away (ground distance) from the control tower is the airplane?

Now,

tan15°=

ae=

.: ae = 19033.45

.: the aeroplane is 19033.45 m away from the control tower.

answer: 1inch=7days  

12inch=12*7=84days

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft