Angle 1 and angle 2 form a linear pair. If the measure of angle 1 = (5x+9)º and the measure of angle 2 = (3x+11)º, find the measure of each angle.
X =
angle 1 =
angle 2 =

- linear pairs are supplementary, meaning they add up to 180°

5x + 9 + 3x + 11 = 180

8x + 20 = 180

8x = 160

x = 20

- now plug in.

angle 1: 5(20) + 9 = 100 + 9 = 109°

angle 2: 3(20) + 11 = 60 + 11 = 71°

is this part of a question or something

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204