Isabella is deciding between two parking garages. Garage A charges an initial fee of $4 to park plus $3 per hour. Garage B charges an initial fee of $12 to park plus $2 per
hour. Let A represent the amount Garage A would charge if Isabella parks for t
hours, and let B represent the amount Garage B would charge if Isabella parks fort
hours. Write an equation for each situation, in terms of t, and determine the hours
parked, t, that would make the cost of each garage the same.

1. A = 4 + 3t 1

  B = 12 + 2t 2

2. 8 hours

Step-by-step explanation:

For park A,

A = 4 + 3t 1

where A is the amount paid, and t is the number of hours.

For park B,

B = 12 + 2t 2

where B is the amount paid, and t is the number of hours.

The hours that would make A = B can be determined as follows.

Equate 1 and 2, so that;

A = B

4 + 3t = 12 + 2t

collect like terms

3t - 2t = 12 - 4

t = 8

The number of hours that would make the cost of each garage the same is 8.

its c or d   take a lucky guess my dude

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40