Den URA - Add/sub/monomials Practice
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Rectangle ABCD has a length represented by the expression 2x - 3, and a width
represented by the expression 4x + 5. Rectangle PQRS has a length represented by
the expression x - 1, and a width represented by the expression 3x + 2. Which are used to represent the difference in the perimeters of
Rectangle ABCD and Rectangle PQRS

Perimeter of ABCD - Perimeter of PQRS = 4x + 2

Step-by-step explanation:

i. For rectangle ABCD;

length, l = 2x -3

width, w = 4x + 5

Perimeter of a rectangle = 2(l + w)

Perimeter of ABCD = 2((2x -3) + (4x + 5))

                                = 2(2x -3 + 4x + 5)

                                = 2(6x + 2)

Perimeter of ABCD = 12x + 4

ii. For rectangle PQRS;

length, l = x - 1

width, w = 3x + 2

Perimeter of a rectangle = 2(l + w)

Perimeter of PQRS = 2((x - 1) + (3x + 2))

                                = 2(x - 1 + 3x + 2)

                                = 2(4x + 1)

Perimeter of PQRS = 8x + 2

So that,

Perimeter of ABCD - Perimeter of PQRS = (12x + 4) - (8x + 2)

                                          = 12x + 4 - 8x - 2

                                          = 4x + 2

Perimeter of ABCD - Perimeter of PQRS = 4x + 2

2 x t divided by n

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752