does anyone know how to solve 2x+3y=7 and 4x-5y=25 using substitution to solve the system of equations. PLEASE HELP ONLY IF YK IT

Step-by-step explanation:

first, let us mark the two equations as i and ii

2x+ 3y = 7

or, 2x = 7-3y

or, x = (7-3y) ÷ 2(i)

and let 4x-5y= 25(ii)

Now, put the the value of x from (i) into (ii)

4[(7-3y) / 2] -5y = 25

2(7-3y) -5y = 25

14- 6y - 5y = 25

-11y = 11

y = -1

Now, put y = -1 back in (i)

x = (7-3y)/2

x = 10 /2

x = 5

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl