Find the limit, if it exists.
Lim (2x^3+x^2+7)
X->2

27

Step-by-step explanation:

In this case, because we have a polynomial where all x-values exist, we can plug the value (x=2) straight into the function:

The limit of (2x^3+x^2+7) as x approaches 2 equals 27, which makes sense since the value of (2x^3+x^2+7) at x = 2 is 27.

if x decreases by 4 then y increases by 10

step-by-step explanation:

4.08%

step-by-step explanation: