4. April rewrote a quadratic function in vertex form. h(x) = 5x2 – 30x + 30
Step 1: h(x) = 5(x2 - 6x+ ) + 30
Step 2: h(x) = 5(x2 - 6x + 9) + 30 – 45
Step 3: h(x) = 5(x - 3)2 + 15
April said that the vertex is (3,15). Is April correct? If not, identify the step
in which April made the mistake and correct her work.

the solution is 12x-6y

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

im here

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)