If the area of a rectangle with length (4x) is 4x2 + 12x, find the width.

The width of a rectangle is: w = x+3

Step-by-step explanation:

Given

The length of rectangle = l = 4x

The area of rectangle = A = 4x² + 12x

To determine

The width of rectangle = w = ?

We know that the formula of the area of the rectangle is

substitute A = 4x² + 12x and l = 4x in the equation to determine the width w of the rectangle

4x² + 12x = w×4x

w = [4x² + 12x] / [4x]

Factor 4x² + 12x:   4x(x+3)

w = [ 4x(x+3) ] /  [4x]

w = x+3

Therefore, the width of a rectangle is: w = x+3

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

30005

yes ok