The height above the ground of a stone thrown upwards is given by s(t), where t is measured in seconds. After I second, the height of the stone is 48 feet above the ground, and after 1.5 seconds, the height of the stone is 60 feet above the ground. Evaluates(1) ands(1.5), and then find the average velocity of the stone over the time interval [1, 1.5).

what do you need me to answer?

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

i dont know what you want me to answer for this but im guessing 2: 11?