A frame designer is making a triangular frame. She has two sides of length 18 inches and 27 inches. What are the possible lengths (in whole inches) for the third side?

Therefore, the possible lengths (in whole inches) for the third side is

9 inches < x < 45 inches

Step-by-step explanation:

For the above question, we have a rule, the sum of the length of any two sides of the triangle must be greater than the length of the third side.

Hence:

She has two sides of length 18 inches and 27 inches

Let the third side = x

Hence:

a) 18 + 27 > x

45 > x

b) 18 + x > 27

x > 27 - 18

x > 9

Therefore, the possible lengths (in whole inches) for the third side is

9 inches < x < 45 inches

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.