Find the coordinates of the midpoint for line segment JK if J(-9, 5) and K(21.-7)

(6, -1)

Step-by-step explanation:

The coordinates of the midpoint of a line is [(x₁ + x₂)/2, (y₁ + y₂)/2]. For the given line, JK where J = (-9, 5) = (x₁, y₁) and K = (21,-7) = (x₂, y₂).

So [(x₁ + x₂)/2, (y₁ + y₂)/2]

= [(-9 + 21)/2, (5 + (-7))/2]

= [12/2, (5 - 7)/2]

= [12/2, -2/2]

= (6, -1)

c. (3,2,6) is the answer.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3